Solve for A
A=16\sqrt{3}+28\approx 55.712812921
Assign A
A≔16\sqrt{3}+28
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A=16+16\sqrt{3}+4\left(\sqrt{3}\right)^{2}
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(4+2\sqrt{3}\right)^{2}.
A=16+16\sqrt{3}+4\times 3
The square of \sqrt{3} is 3.
A=16+16\sqrt{3}+12
Multiply 4 and 3 to get 12.
A=28+16\sqrt{3}
Add 16 and 12 to get 28.
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