Solve A=(3^{2}-2^{3})^{2016}+(2^4-4^2)^20*3^10+2

$$A = ( 3 ^ { 2 } - 2 ^ { 3 } ) ^ { 2016 } + ( 2 ^ { 4 } - 4 ^ { 2 } ) ^ { 20 } \cdot 3 ^ { 10 } + 2$$

Solve for A

$$A=3$$

Steps for Solving Linear Equation

Calculate 3 to the power of 2 and get 9.

$$A=\left(9-2^{3}\right)^{2016}+\left(2^{4}-4^{2}\right)^{20}\times 3^{10}+2$$

Calculate 2 to the power of 3 and get 8.

$$A=\left(9-8\right)^{2016}+\left(2^{4}-4^{2}\right)^{20}\times 3^{10}+2$$

Subtract 8 from 9 to get 1.

$$A=1^{2016}+\left(2^{4}-4^{2}\right)^{20}\times 3^{10}+2$$

Calculate 1 to the power of 2016 and get 1.

$$A=1+\left(2^{4}-4^{2}\right)^{20}\times 3^{10}+2$$

Calculate 2 to the power of 4 and get 16.

$$A=1+\left(16-4^{2}\right)^{20}\times 3^{10}+2$$

Calculate 4 to the power of 2 and get 16.

$$A=1+\left(16-16\right)^{20}\times 3^{10}+2$$

Subtract 16 from 16 to get 0.

$$A=1+0^{20}\times 3^{10}+2$$

Calculate 0 to the power of 20 and get 0.

$$A=1+0\times 3^{10}+2$$

Calculate 3 to the power of 10 and get 59049.

$$A=1+0\times 59049+2$$

Multiply 0 and 59049 to get 0.

$$A=1+0+2$$

Add 1 and 0 to get 1.

$$A=1+2$$

Add 1 and 2 to get 3.

$$A=3$$

Assign A

$$A≔3$$