Solve A=(sqrt{3}-sqrt{2})(sqrt{3}-sqrt{2})

$$A = ( \sqrt { 3 } - \sqrt { 2 } ) ( \sqrt { 3 } - \sqrt { 2 } )$$

Solve for A

$$A=5-2\sqrt{6}\approx 0.101020514$$

Steps for Solving Linear Equation

Multiply \sqrt{3}-\sqrt{2} and \sqrt{3}-\sqrt{2} to get \left(\sqrt{3}-\sqrt{2}\right)^{2}.

$$A=\left(\sqrt{3}-\sqrt{2}\right)^{2}$$

Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(\sqrt{3}-\sqrt{2}\right)^{2}.

$$A=\left(\sqrt{3}\right)^{2}-2\sqrt{3}\sqrt{2}+\left(\sqrt{2}\right)^{2}$$

The square of \sqrt{3} is 3.

$$A=3-2\sqrt{3}\sqrt{2}+\left(\sqrt{2}\right)^{2}$$

To multiply \sqrt{3} and \sqrt{2}, multiply the numbers under the square root.

$$A=3-2\sqrt{6}+\left(\sqrt{2}\right)^{2}$$

The square of \sqrt{2} is 2.

$$A=3-2\sqrt{6}+2$$

Add 3 and 2 to get 5.

$$A=5-2\sqrt{6}$$

Assign A

$$A≔5-2\sqrt{6}$$