A = \sqrt[ 3 ] { 0,001 } + 3 \cdot \sqrt { \frac { 25 } { 9 } }
Solve for A
A=5,1
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A≔5,1
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A=\frac{1}{10}+3\sqrt{\frac{25}{9}}
Calculate \sqrt[3]{0,001} and get \frac{1}{10}.
A=\frac{1}{10}+3\times \frac{5}{3}
Rewrite the square root of the division \frac{25}{9} as the division of square roots \frac{\sqrt{25}}{\sqrt{9}}. Take the square root of both numerator and denominator.
A=\frac{1}{10}+5
Multiply 3 and \frac{5}{3} to get 5.
A=\frac{51}{10}
Add \frac{1}{10} and 5 to get \frac{51}{10}.
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