Solve for A
A=\sqrt[3]{2}\approx 1.25992105
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A≔\sqrt[3]{2}
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A=\sqrt[15]{32}
Calculate 2 to the power of 5 and get 32.
\sqrt[15]{32}=\sqrt[15]{2^{5}}=2^{\frac{5}{15}}=2^{\frac{1}{3}}=\sqrt[3]{2}
Rewrite \sqrt[15]{32} as \sqrt[15]{2^{5}}. Convert from radical to exponential form and cancel out 5 in the exponent. Convert back to radical form.
A=\sqrt[3]{2}
Insert the obtained value back in the expression.
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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
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Limits
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