Solve A=piAB

$$A = \pi A B$$

Solve for A

$$\left\{\begin{matrix}\\A=0\text{, }&\text{unconditionally}\\A\in \mathrm{R}\text{, }&B=\frac{1}{\pi }\end{matrix}\right.$$

Steps for Solving Linear Equation

Subtract \pi AB from both sides.

$$A-\pi AB=0$$

Reorder the terms.

$$-\pi AB+A=0$$

Combine all terms containing A.

$$\left(-\pi B+1\right)A=0$$

The equation is in standard form.

$$\left(1-\pi B\right)A=0$$

Divide 0 by 1-\pi B.

$$A=0$$

Solve for B

$$\left\{\begin{matrix}\\B=\frac{1}{\pi }\text{, }&\text{unconditionally}\\B\in \mathrm{R}\text{, }&A=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$\pi AB=A$$

Divide both sides by \pi A.

$$\frac{\pi AB}{\pi A}=\frac{A}{\pi A}$$

Dividing by \pi A undoes the multiplication by \pi A.

$$B=\frac{A}{\pi A}$$

Divide A by \pi A.

$$B=\frac{1}{\pi }$$