Solve A=pi^2+2rx

$$A = \pi ^ { 2 } + 2 r x$$

Solve for r (complex solution)

$$\left\{\begin{matrix}r=-\frac{\pi ^{2}-A}{2x}\text{, }&x\neq 0\\r\in \mathrm{C}\text{, }&A=\pi ^{2}\text{ and }x=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$\pi ^{2}+2rx=A$$

Subtract \pi ^{2} from both sides.

$$2rx=A-\pi ^{2}$$

The equation is in standard form.

$$2xr=A-\pi ^{2}$$

Divide both sides by 2x.

$$\frac{2xr}{2x}=\frac{A-\pi ^{2}}{2x}$$

Dividing by 2x undoes the multiplication by 2x.

$$r=\frac{A-\pi ^{2}}{2x}$$

Solve for r

$$\left\{\begin{matrix}r=-\frac{\pi ^{2}-A}{2x}\text{, }&x\neq 0\\r\in \mathrm{R}\text{, }&A=\pi ^{2}\text{ and }x=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$\pi ^{2}+2rx=A$$

Subtract \pi ^{2} from both sides.

$$2rx=A-\pi ^{2}$$

The equation is in standard form.

$$2xr=A-\pi ^{2}$$

Divide both sides by 2x.

$$\frac{2xr}{2x}=\frac{A-\pi ^{2}}{2x}$$

Dividing by 2x undoes the multiplication by 2x.

$$r=\frac{A-\pi ^{2}}{2x}$$

Solve for A

$$A=2rx+\pi ^{2}$$