Solve for b
b=2A-h
Solve for A
A=\frac{b+h}{2}
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A=\frac{1}{2}b+\frac{1}{2}h
Divide each term of b+h by 2 to get \frac{1}{2}b+\frac{1}{2}h.
\frac{1}{2}b+\frac{1}{2}h=A
Swap sides so that all variable terms are on the left hand side.
\frac{1}{2}b=A-\frac{1}{2}h
Subtract \frac{1}{2}h from both sides.
\frac{1}{2}b=-\frac{h}{2}+A
The equation is in standard form.
\frac{\frac{1}{2}b}{\frac{1}{2}}=\frac{-\frac{h}{2}+A}{\frac{1}{2}}
Multiply both sides by 2.
b=\frac{-\frac{h}{2}+A}{\frac{1}{2}}
Dividing by \frac{1}{2} undoes the multiplication by \frac{1}{2}.
b=2A-h
Divide A-\frac{h}{2} by \frac{1}{2} by multiplying A-\frac{h}{2} by the reciprocal of \frac{1}{2}.
A=\frac{1}{2}b+\frac{1}{2}h
Divide each term of b+h by 2 to get \frac{1}{2}b+\frac{1}{2}h.
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