Solve A=B+b/2

$$A = \frac { B + b } { 2 }$$

Solve for B

$$B=2A-b$$

Steps for Solving Linear Equation

Divide each term of B+b by 2 to get \frac{1}{2}B+\frac{1}{2}b.

$$A=\frac{1}{2}B+\frac{1}{2}b$$

Swap sides so that all variable terms are on the left hand side.

$$\frac{1}{2}B+\frac{1}{2}b=A$$

Subtract \frac{1}{2}b from both sides.

$$\frac{1}{2}B=A-\frac{1}{2}b$$

The equation is in standard form.

$$\frac{1}{2}B=-\frac{b}{2}+A$$

Multiply both sides by 2.

$$\frac{\frac{1}{2}B}{\frac{1}{2}}=\frac{-\frac{b}{2}+A}{\frac{1}{2}}$$

Dividing by \frac{1}{2} undoes the multiplication by \frac{1}{2}.

$$B=\frac{-\frac{b}{2}+A}{\frac{1}{2}}$$

Divide A-\frac{b}{2} by \frac{1}{2} by multiplying A-\frac{b}{2} by the reciprocal of \frac{1}{2}.

$$B=2A-b$$

Solve for A

$$A=\frac{B+b}{2}$$

Solution Steps

Divide each term of B+b by 2 to get \frac{1}{2}B+\frac{1}{2}b.

$$A=\frac{1}{2}B+\frac{1}{2}b$$