Solve A=5-a2x/0,8

$$A = \frac { 5 - a 2 x } { 0,8 }$$

Solve for A

$$A=\frac{25-5a_{2}x}{4}$$

Solution Steps

Divide each term of 5-a_{2}x by 0,8 to get \frac{5}{0,8}+\frac{-a_{2}x}{0,8}.

$$A=\frac{5}{0,8}+\frac{-a_{2}x}{0,8}$$

Expand \frac{5}{0,8} by multiplying both numerator and the denominator by 10.

$$A=\frac{50}{8}+\frac{-a_{2}x}{0,8}$$

Reduce the fraction \frac{50}{8} to lowest terms by extracting and canceling out 2.

$$A=\frac{25}{4}+\frac{-a_{2}x}{0,8}$$

Divide -a_{2}x by 0,8 to get -1,25a_{2}x.

$$A=\frac{25}{4}-1,25a_{2}x$$

Solve for a_2

$$\left\{\begin{matrix}a_{2}=\frac{25-4A}{5x}\text{, }&x\neq 0\\a_{2}\in \mathrm{R}\text{, }&A=\frac{25}{4}\text{ and }x=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Divide each term of 5-a_{2}x by 0,8 to get \frac{5}{0,8}+\frac{-a_{2}x}{0,8}.

$$A=\frac{5}{0,8}+\frac{-a_{2}x}{0,8}$$

Expand \frac{5}{0,8} by multiplying both numerator and the denominator by 10.

$$A=\frac{50}{8}+\frac{-a_{2}x}{0,8}$$

Reduce the fraction \frac{50}{8} to lowest terms by extracting and canceling out 2.

$$A=\frac{25}{4}+\frac{-a_{2}x}{0,8}$$

Divide -a_{2}x by 0,8 to get -1,25a_{2}x.

$$A=\frac{25}{4}-1,25a_{2}x$$

Swap sides so that all variable terms are on the left hand side.

$$\frac{25}{4}-1,25a_{2}x=A$$

Subtract \frac{25}{4} from both sides.

$$-1,25a_{2}x=A-\frac{25}{4}$$

The equation is in standard form.

$$\left(-\frac{5x}{4}\right)a_{2}=A-\frac{25}{4}$$

Divide both sides by -1,25x.

$$\frac{\left(-\frac{5x}{4}\right)a_{2}}{-\frac{5x}{4}}=\frac{A-\frac{25}{4}}{-\frac{5x}{4}}$$

Dividing by -1,25x undoes the multiplication by -1,25x.

$$a_{2}=\frac{A-\frac{25}{4}}{-\frac{5x}{4}}$$

Divide A-\frac{25}{4} by -1,25x.

$$a_{2}=-\frac{4A-25}{5x}$$