Solve for x
x=\frac{5A-4}{3}
Solve for A
A=\frac{3x+4}{5}
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A=\frac{3}{5}x+\frac{4}{5}
Divide each term of 3x+4 by 5 to get \frac{3}{5}x+\frac{4}{5}.
\frac{3}{5}x+\frac{4}{5}=A
Swap sides so that all variable terms are on the left hand side.
\frac{3}{5}x=A-\frac{4}{5}
Subtract \frac{4}{5} from both sides.
\frac{\frac{3}{5}x}{\frac{3}{5}}=\frac{A-\frac{4}{5}}{\frac{3}{5}}
Divide both sides of the equation by \frac{3}{5}, which is the same as multiplying both sides by the reciprocal of the fraction.
x=\frac{A-\frac{4}{5}}{\frac{3}{5}}
Dividing by \frac{3}{5} undoes the multiplication by \frac{3}{5}.
x=\frac{5A-4}{3}
Divide A-\frac{4}{5} by \frac{3}{5} by multiplying A-\frac{4}{5} by the reciprocal of \frac{3}{5}.
A=\frac{3}{5}x+\frac{4}{5}
Divide each term of 3x+4 by 5 to get \frac{3}{5}x+\frac{4}{5}.
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