Solve for A
A=\frac{3x^{2}}{4}-\frac{y^{2}}{2}-\frac{z^{2}}{3}
Solve for x
x=\frac{\sqrt{6y^{2}+4z^{2}+12A}}{3}
x=-\frac{\sqrt{6y^{2}+4z^{2}+12A}}{3}\text{, }A\geq -\frac{y^{2}}{2}-\frac{z^{2}}{3}
Quiz
Algebra
A = \frac { 3 } { 4 } x ^ { 2 } - \frac { 1 } { 2 } y ^ { 2 } - \frac { 1 } { 3 } z ^ { 2 }
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