Solve for B
B=\frac{9A}{2}+C
Solve for A
A=\frac{2\left(B-C\right)}{9}
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A=\frac{2}{9}B-\frac{2}{9}C
Use the distributive property to multiply \frac{2}{9} by B-C.
\frac{2}{9}B-\frac{2}{9}C=A
Swap sides so that all variable terms are on the left hand side.
\frac{2}{9}B=A+\frac{2}{9}C
Add \frac{2}{9}C to both sides.
\frac{2}{9}B=\frac{2C}{9}+A
The equation is in standard form.
\frac{\frac{2}{9}B}{\frac{2}{9}}=\frac{\frac{2C}{9}+A}{\frac{2}{9}}
Divide both sides of the equation by \frac{2}{9}, which is the same as multiplying both sides by the reciprocal of the fraction.
B=\frac{\frac{2C}{9}+A}{\frac{2}{9}}
Dividing by \frac{2}{9} undoes the multiplication by \frac{2}{9}.
B=\frac{9A}{2}+C
Divide A+\frac{2C}{9} by \frac{2}{9} by multiplying A+\frac{2C}{9} by the reciprocal of \frac{2}{9}.
A=\frac{2}{9}B-\frac{2}{9}C
Use the distributive property to multiply \frac{2}{9} by B-C.
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