Solve A=2^3/3-2^2/2+4(2)=

$$A = \frac { 2 ^ { 3 } } { 3 } - \frac { 2 ^ { 2 } } { 2 } + 4 ( 2 ) =$$

Solve for A

$$A = \frac{26}{3} = 8\frac{2}{3} \approx 8.666666667$$

Steps for Solving Linear Equation

To divide powers of the same base, subtract the denominator's exponent from the numerator's exponent. Subtract 1 from 2 to get 1.

$$A=\frac{2^{3}}{3}-2^{1}+4\times 2$$

Calculate 2 to the power of 3 and get 8.

$$A=\frac{8}{3}-2^{1}+4\times 2$$

Calculate 2 to the power of 1 and get 2.

$$A=\frac{8}{3}-2+4\times 2$$

Convert 2 to fraction \frac{6}{3}.

$$A=\frac{8}{3}-\frac{6}{3}+4\times 2$$

Since \frac{8}{3} and \frac{6}{3} have the same denominator, subtract them by subtracting their numerators.

$$A=\frac{8-6}{3}+4\times 2$$

Subtract 6 from 8 to get 2.

$$A=\frac{2}{3}+4\times 2$$

Multiply 4 and 2 to get 8.

$$A=\frac{2}{3}+8$$

Convert 8 to fraction \frac{24}{3}.

$$A=\frac{2}{3}+\frac{24}{3}$$

Since \frac{2}{3} and \frac{24}{3} have the same denominator, add them by adding their numerators.

$$A=\frac{2+24}{3}$$

Add 2 and 24 to get 26.

$$A=\frac{26}{3}$$

Assign A

$$A≔\frac{26}{3}$$