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A=\frac{2+\sqrt{3}}{\left(2-\sqrt{3}\right)\left(2+\sqrt{3}\right)}
Rationalize the denominator of \frac{1}{2-\sqrt{3}} by multiplying numerator and denominator by 2+\sqrt{3}.
A=\frac{2+\sqrt{3}}{2^{2}-\left(\sqrt{3}\right)^{2}}
Consider \left(2-\sqrt{3}\right)\left(2+\sqrt{3}\right). Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.
A=\frac{2+\sqrt{3}}{4-3}
Square 2. Square \sqrt{3}.
A=\frac{2+\sqrt{3}}{1}
Subtract 3 from 4 to get 1.
A=2+\sqrt{3}
Anything divided by one gives itself.