Solve A=1/2h(B+b);A=65,B=8,b=5

$$A = \frac { 1 } { 2 } h ( B + b ) ; A = 65 , B = 8 , b = 5$$

Solve for A, h, B, b

$$A=65$$

$$h=10$$

$$B=8$$

$$b=5$$

Solution Steps

Consider the first equation. Insert the known values of variables into the equation.

$$65=\frac{1}{2}h\left(8+5\right)$$

Add 8 and 5 to get 13.

$$65=\frac{1}{2}h\times 13$$

Multiply \frac{1}{2} and 13 to get \frac{13}{2}.

$$65=\frac{13}{2}h$$

Swap sides so that all variable terms are on the left hand side.

$$\frac{13}{2}h=65$$

Multiply both sides by \frac{2}{13}, the reciprocal of \frac{13}{2}.

$$h=65\times \frac{2}{13}$$

Multiply 65 and \frac{2}{13} to get 10.

$$h=10$$

The system is now solved.

$$A=65 h=10 B=8 b=5$$