Solve A=1/2AC*BD

$$A = \frac { 1 } { 2 } A C \cdot B D$$

Solve for A

$$\left\{\begin{matrix}\\A=0\text{, }&\text{unconditionally}\\A\in \mathrm{R}\text{, }&C=\frac{2}{BD}\text{ and }D\neq 0\text{ and }B\neq 0\end{matrix}\right.$$

Steps for Solving Linear Equation

Subtract \frac{1}{2}ACBD from both sides.

$$A-\frac{1}{2}ACBD=0$$

Combine all terms containing A.

$$\left(1-\frac{1}{2}CBD\right)A=0$$

The equation is in standard form.

$$\left(-\frac{BCD}{2}+1\right)A=0$$

Divide 0 by 1-\frac{1}{2}CBD.

$$A=0$$

Solve for B

$$\left\{\begin{matrix}B=\frac{2}{CD}\text{, }&D\neq 0\text{ and }C\neq 0\\B\in \mathrm{R}\text{, }&A=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$\frac{1}{2}ACBD=A$$

The equation is in standard form.

$$\frac{ACD}{2}B=A$$

Divide both sides by \frac{1}{2}ACD.

$$\frac{2\times \frac{ACD}{2}B}{ACD}=\frac{2A}{ACD}$$

Dividing by \frac{1}{2}ACD undoes the multiplication by \frac{1}{2}ACD.

$$B=\frac{2A}{ACD}$$

Divide A by \frac{1}{2}ACD.

$$B=\frac{2}{CD}$$