Solve A=[frac{16^-0.25+(-8)^-frac{1{3}}}{4^-0.5-9^-0.5}]

$$A = [ \frac { 16 ^ { - 0.25 } + ( - 8 ) ^ { - \frac { 1 } { 3 } } } { 4 ^ { - 0.5 } - 9 ^ { - 0.5 } } ]$$

Solve for A

$$A=0$$

Steps for Solving Linear Equation

Calculate 16 to the power of -0.25 and get \frac{1}{2}.

$$A=\frac{\frac{1}{2}+\left(-8\right)^{-\frac{1}{3}}}{4^{-0.5}-9^{-0.5}}$$

Calculate -8 to the power of -\frac{1}{3} and get -\frac{1}{2}.

$$A=\frac{\frac{1}{2}-\frac{1}{2}}{4^{-0.5}-9^{-0.5}}$$

Subtract \frac{1}{2} from \frac{1}{2} to get 0.

$$A=\frac{0}{4^{-0.5}-9^{-0.5}}$$

Calculate 4 to the power of -0.5 and get \frac{1}{2}.

$$A=\frac{0}{\frac{1}{2}-9^{-0.5}}$$

Calculate 9 to the power of -0.5 and get \frac{1}{3}.

$$A=\frac{0}{\frac{1}{2}-\frac{1}{3}}$$

Subtract \frac{1}{3} from \frac{1}{2} to get \frac{1}{6}.

$$A=\frac{0}{\frac{1}{6}}$$

Zero divided by any non-zero number gives zero.

$$A=0$$

Assign A

$$A≔0$$