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A=3\sqrt{11}+5\times 2\sqrt{11}-3\sqrt{99}
Factor 44=2^{2}\times 11. Rewrite the square root of the product \sqrt{2^{2}\times 11} as the product of square roots \sqrt{2^{2}}\sqrt{11}. Take the square root of 2^{2}.
A=3\sqrt{11}+10\sqrt{11}-3\sqrt{99}
Multiply 5 and 2 to get 10.
A=13\sqrt{11}-3\sqrt{99}
Combine 3\sqrt{11} and 10\sqrt{11} to get 13\sqrt{11}.
A=13\sqrt{11}-3\times 3\sqrt{11}
Factor 99=3^{2}\times 11. Rewrite the square root of the product \sqrt{3^{2}\times 11} as the product of square roots \sqrt{3^{2}}\sqrt{11}. Take the square root of 3^{2}.
A=13\sqrt{11}-9\sqrt{11}
Multiply -3 and 3 to get -9.
A=4\sqrt{11}
Combine 13\sqrt{11} and -9\sqrt{11} to get 4\sqrt{11}.