Solve for B
\left\{\begin{matrix}B=-\frac{A-FJ-V}{C}\text{, }&C\neq 0\\B\in \mathrm{R}\text{, }&A=FJ+V\text{ and }C=0\end{matrix}\right.
Solve for A
A=V+FJ-BC
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BC=V+FJ-A
Subtract A from both sides.
CB=V+FJ-A
The equation is in standard form.
\frac{CB}{C}=\frac{V+FJ-A}{C}
Divide both sides by C.
B=\frac{V+FJ-A}{C}
Dividing by C undoes the multiplication by C.
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