Solve A+411B+533Y=9010*135

$$A + 411 B + 533 Y = 9010 \cdot 135$$

Solve for A

$$A=1216350-533Y-411B$$

Solution Steps

Multiply 9010 and 135 to get 1216350.

$$A+411B+533Y=1216350$$

Subtract 411B from both sides.

$$A+533Y=1216350-411B$$

Subtract 533Y from both sides.

$$A=1216350-411B-533Y$$

Solve for B

$$B=-\frac{A}{411}-\frac{533Y}{411}+\frac{405450}{137}$$

Steps for Solving Linear Equation

Multiply 9010 and 135 to get 1216350.

$$A+411B+533Y=1216350$$

Subtract A from both sides.

$$411B+533Y=1216350-A$$

Subtract 533Y from both sides.

$$411B=1216350-A-533Y$$

The equation is in standard form.

$$411B=1216350-533Y-A$$

Divide both sides by 411.

$$\frac{411B}{411}=\frac{1216350-533Y-A}{411}$$

Dividing by 411 undoes the multiplication by 411.

$$B=\frac{1216350-533Y-A}{411}$$

Divide 1216350-A-533Y by 411.

$$B=-\frac{A}{411}-\frac{533Y}{411}+\frac{405450}{137}$$