Solve for x
x=\frac{2y}{9}+\frac{5}{3}
Solve for y
y=\frac{9x-15}{2}
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9x-15=2y
Add 2y to both sides. Anything plus zero gives itself.
9x=2y+15
Add 15 to both sides.
\frac{9x}{9}=\frac{2y+15}{9}
Divide both sides by 9.
x=\frac{2y+15}{9}
Dividing by 9 undoes the multiplication by 9.
x=\frac{2y}{9}+\frac{5}{3}
Divide 2y+15 by 9.
-2y-15=-9x
Subtract 9x from both sides. Anything subtracted from zero gives its negation.
-2y=-9x+15
Add 15 to both sides.
-2y=15-9x
The equation is in standard form.
\frac{-2y}{-2}=\frac{15-9x}{-2}
Divide both sides by -2.
y=\frac{15-9x}{-2}
Dividing by -2 undoes the multiplication by -2.
y=\frac{9x-15}{2}
Divide -9x+15 by -2.
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