Solve for x
x=\frac{10y}{9}+\frac{4}{3}
Solve for y
y=\frac{9x}{10}-\frac{6}{5}
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9x=12+10y
Add 10y to both sides.
9x=10y+12
The equation is in standard form.
\frac{9x}{9}=\frac{10y+12}{9}
Divide both sides by 9.
x=\frac{10y+12}{9}
Dividing by 9 undoes the multiplication by 9.
x=\frac{10y}{9}+\frac{4}{3}
Divide 12+10y by 9.
-10y=12-9x
Subtract 9x from both sides.
\frac{-10y}{-10}=\frac{12-9x}{-10}
Divide both sides by -10.
y=\frac{12-9x}{-10}
Dividing by -10 undoes the multiplication by -10.
y=\frac{9x}{10}-\frac{6}{5}
Divide 12-9x by -10.
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