Solve for x
x=-\frac{4y}{9}+\frac{1}{3}
Solve for y
y=\frac{3-9x}{4}
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9x=3-4y
Subtract 4y from both sides.
\frac{9x}{9}=\frac{3-4y}{9}
Divide both sides by 9.
x=\frac{3-4y}{9}
Dividing by 9 undoes the multiplication by 9.
x=-\frac{4y}{9}+\frac{1}{3}
Divide 3-4y by 9.
4y=3-9x
Subtract 9x from both sides.
\frac{4y}{4}=\frac{3-9x}{4}
Divide both sides by 4.
y=\frac{3-9x}{4}
Dividing by 4 undoes the multiplication by 4.
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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
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Limits
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