Solve 9x+1geq45x-2

$$9x+1 \geq 45x-2$$

Solve for x

$$x\leq \frac{1}{12}$$

Solution Steps

Subtract 45x from both sides.

$$9x+1-45x\geq -2$$

Combine 9x and -45x to get -36x.

$$-36x+1\geq -2$$

Subtract 1 from both sides.

$$-36x\geq -2-1$$

Subtract 1 from -2 to get -3.

$$-36x\geq -3$$

Divide both sides by -36. Since -36 is negative, the inequality direction is changed.

$$x\leq \frac{-3}{-36}$$

Reduce the fraction \frac{-3}{-36} to lowest terms by extracting and canceling out -3.

$$x\leq \frac{1}{12}$$