Solve 99sqrt{3}(sqrt{x+1})=1

$$99 \sqrt { 3 } ( \sqrt { x + 1 } ) = 1$$

Solve for x

$$x=-\frac{29402}{29403}\approx -0.99996599$$

Steps for Solving Radical Equations

Divide both sides by 99\sqrt{3}.

$$\frac{99\sqrt{3}\sqrt{x+1}}{99\sqrt{3}}=\frac{1}{99\sqrt{3}}$$

Dividing by 99\sqrt{3} undoes the multiplication by 99\sqrt{3}.

$$\sqrt{x+1}=\frac{1}{99\sqrt{3}}$$

Divide 1 by 99\sqrt{3}.

$$\sqrt{x+1}=\frac{\sqrt{3}}{297}$$

Square both sides of the equation.

$$x+1=\frac{1}{29403}$$

Subtract 1 from both sides of the equation.

$$x+1-1=\frac{1}{29403}-1$$

Subtracting 1 from itself leaves 0.

$$x=\frac{1}{29403}-1$$

Subtract 1 from \frac{1}{29403}.

$$x=-\frac{29402}{29403}$$