Solve 99*5-[20:(13-3*3)+1]-4:8}:6+(15-12+6

$$99 \cdot 5 - [ 20 : ( 13 - 3 \cdot 3 ) + 1 ] - 4 : 8 \} : 6 + ( 15 - 12 + 6$$

Evaluate

$$\frac{977}{2}=488.5$$

Solution Steps

Multiply 99 and 5 to get 495.

$$495-\left(\frac{20}{13-3\times 3}+1\right)-\frac{4}{8}$$

Multiply 3 and 3 to get 9.

$$495-\left(\frac{20}{13-9}+1\right)-\frac{4}{8}$$

Subtract 9 from 13 to get 4.

$$495-\left(\frac{20}{4}+1\right)-\frac{4}{8}$$

Divide 20 by 4 to get 5.

$$495-\left(5+1\right)-\frac{4}{8}$$

Add 5 and 1 to get 6.

$$495-6-\frac{4}{8}$$

Subtract 6 from 495 to get 489.

$$489-\frac{4}{8}$$

Reduce the fraction \frac{4}{8} to lowest terms by extracting and canceling out 4.

$$489-\frac{1}{2}$$

Convert 489 to fraction \frac{978}{2}.

$$\frac{978}{2}-\frac{1}{2}$$

Since \frac{978}{2} and \frac{1}{2} have the same denominator, subtract them by subtracting their numerators.

$$\frac{978-1}{2}$$

Subtract 1 from 978 to get 977.

$$\frac{977}{2}$$

Factor

$$\frac{977}{2} = 488\frac{1}{2} = 488.5$$