Solve 95=x^2+1

$$95 = x ^ { 2 } + 1$$

Solve for x

$$x=\sqrt{94}\approx 9.695359715$$

$$x=-\sqrt{94}\approx -9.695359715$$

Steps by Finding Square Root

Swap sides so that all variable terms are on the left hand side.

$$x^{2}+1=95$$

Subtract 1 from both sides.

$$x^{2}=95-1$$

Subtract 1 from 95 to get 94.

$$x^{2}=94$$

Take the square root of both sides of the equation.

$$x=\sqrt{94} x=-\sqrt{94}$$

Steps Using the Quadratic Formula

Swap sides so that all variable terms are on the left hand side.

$$x^{2}+1=95$$

Subtract 95 from both sides.

$$x^{2}+1-95=0$$

Subtract 95 from 1 to get -94.

$$x^{2}-94=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -94 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-94\right)}}{2}$$

Square 0.

$$x=\frac{0±\sqrt{-4\left(-94\right)}}{2}$$

Multiply -4 times -94.

$$x=\frac{0±\sqrt{376}}{2}$$

Take the square root of 376.

$$x=\frac{0±2\sqrt{94}}{2}$$

Now solve the equation x=\frac{0±2\sqrt{94}}{2} when ± is plus.

$$x=\sqrt{94}$$

Now solve the equation x=\frac{0±2\sqrt{94}}{2} when ± is minus.

$$x=-\sqrt{94}$$

The equation is now solved.

$$x=\sqrt{94} x=-\sqrt{94}$$