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Solve for x (complex solution)
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6^{2x+1}=95
Swap sides so that all variable terms are on the left hand side.
\log(6^{2x+1})=\log(95)
Take the logarithm of both sides of the equation.
\left(2x+1\right)\log(6)=\log(95)
The logarithm of a number raised to a power is the power times the logarithm of the number.
2x+1=\frac{\log(95)}{\log(6)}
Divide both sides by \log(6).
2x+1=\log_{6}\left(95\right)
By the change-of-base formula \frac{\log(a)}{\log(b)}=\log_{b}\left(a\right).
2x=\log_{6}\left(95\right)-1
Subtract 1 from both sides of the equation.
x=\frac{\log_{6}\left(95\right)-1}{2}
Divide both sides by 2.