Solve for T
T=3\log_{\frac{3}{50}}\left(\frac{21}{20}\right)\approx -0.052025995
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\frac{9261}{8000}=\left(\frac{1+5}{100}\right)^{T}
Divide both sides by 8000.
\frac{9261}{8000}=\left(\frac{6}{100}\right)^{T}
Add 1 and 5 to get 6.
\frac{9261}{8000}=\left(\frac{3}{50}\right)^{T}
Reduce the fraction \frac{6}{100} to lowest terms by extracting and canceling out 2.
\left(\frac{3}{50}\right)^{T}=\frac{9261}{8000}
Swap sides so that all variable terms are on the left hand side.
\log(\left(\frac{3}{50}\right)^{T})=\log(\frac{9261}{8000})
Take the logarithm of both sides of the equation.
T\log(\frac{3}{50})=\log(\frac{9261}{8000})
The logarithm of a number raised to a power is the power times the logarithm of the number.
T=\frac{\log(\frac{9261}{8000})}{\log(\frac{3}{50})}
Divide both sides by \log(\frac{3}{50}).
T=\log_{\frac{3}{50}}\left(\frac{9261}{8000}\right)
By the change-of-base formula \frac{\log(a)}{\log(b)}=\log_{b}\left(a\right).
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