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Differentiate w.r.t. x_12
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\begin{array}{c}\phantom{\times99}925\\\underline{\times\phantom{999}12}\\\end{array}
First line up the numbers vertically and match the places from the right like this.
\begin{array}{c}\phantom{\times99}925\\\underline{\times\phantom{999}12}\\\phantom{\times9}1850\\\end{array}
Now multiply the first number with the 1^{st} digit in 2^{nd} number to get intermediate results. That is Multiply 925 with 2. Write the result 1850 at the end leaving 0 spaces to the right like this.
\begin{array}{c}\phantom{\times99}925\\\underline{\times\phantom{999}12}\\\phantom{\times9}1850\\\underline{\phantom{\times9}925\phantom{9}}\\\end{array}
Now multiply the first number with the 2^{nd} digit in 2^{nd} number to get intermediate results. That is Multiply 925 with 1. Write the result 925 at the end leaving 1 spaces to the right like this.
\begin{array}{c}\phantom{\times99}925\\\underline{\times\phantom{999}12}\\\phantom{\times9}1850\\\underline{\phantom{\times9}925\phantom{9}}\\\phantom{\times}11100\end{array}
Now add the intermediate results to get final answer.
925x_{12}^{1-1}
The derivative of ax^{n} is nax^{n-1}.
925x_{12}^{0}
Subtract 1 from 1.
925\times 1
For any term t except 0, t^{0}=1.
925
For any term t, t\times 1=t and 1t=t.