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0.5292=0.5x^{2}
Multiply 9.8 and 0.054 to get 0.5292.
0.5x^{2}=0.5292
Swap sides so that all variable terms are on the left hand side.
x^{2}=\frac{0.5292}{0.5}
Divide both sides by 0.5.
x^{2}=\frac{5292}{5000}
Expand \frac{0.5292}{0.5} by multiplying both numerator and the denominator by 10000.
x^{2}=\frac{1323}{1250}
Reduce the fraction \frac{5292}{5000} to lowest terms by extracting and canceling out 4.
x=\frac{21\sqrt{6}}{50} x=-\frac{21\sqrt{6}}{50}
Take the square root of both sides of the equation.
0.5292=0.5x^{2}
Multiply 9.8 and 0.054 to get 0.5292.
0.5x^{2}=0.5292
Swap sides so that all variable terms are on the left hand side.
0.5x^{2}-0.5292=0
Subtract 0.5292 from both sides.
\frac{1}{2}x^{2}-0.5292=0
Quadratic equations like this one, with an x^{2} term but no x term, can still be solved using the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, once they are put in standard form: ax^{2}+bx+c=0.
x=\frac{0±\sqrt{0^{2}-4\times \frac{1}{2}\left(-0.5292\right)}}{2\times \frac{1}{2}}
This equation is in standard form: ax^{2}+bx+c=0. Substitute \frac{1}{2} for a, 0 for b, and -0.5292 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\times \frac{1}{2}\left(-0.5292\right)}}{2\times \frac{1}{2}}
Square 0.
x=\frac{0±\sqrt{-2\left(-0.5292\right)}}{2\times \frac{1}{2}}
Multiply -4 times \frac{1}{2}.
x=\frac{0±\sqrt{1.0584}}{2\times \frac{1}{2}}
Multiply -2 times -0.5292.
x=\frac{0±\frac{21\sqrt{6}}{50}}{2\times \frac{1}{2}}
Take the square root of 1.0584.
x=\frac{0±\frac{21\sqrt{6}}{50}}{1}
Multiply 2 times \frac{1}{2}.
x=\frac{21\sqrt{6}}{50}
Now solve the equation x=\frac{0±\frac{21\sqrt{6}}{50}}{1} when ± is plus.
x=-\frac{21\sqrt{6}}{50}
Now solve the equation x=\frac{0±\frac{21\sqrt{6}}{50}}{1} when ± is minus.
x=\frac{21\sqrt{6}}{50} x=-\frac{21\sqrt{6}}{50}
The equation is now solved.