Solve 9-3(x+2)geq8x-5

$$9-3(x+2) \geq 8x-5$$

Solve for x

$$x\leq \frac{8}{11}$$

Solution Steps

Use the distributive property to multiply -3 by x+2.

$$9-3x-6\geq 8x-5$$

Subtract 6 from 9 to get 3.

$$3-3x\geq 8x-5$$

Subtract 8x from both sides.

$$3-3x-8x\geq -5$$

Combine -3x and -8x to get -11x.

$$3-11x\geq -5$$

Subtract 3 from both sides.

$$-11x\geq -5-3$$

Subtract 3 from -5 to get -8.

$$-11x\geq -8$$

Divide both sides by -11. Since -11 is negative, the inequality direction is changed.

$$x\leq \frac{-8}{-11}$$

Fraction \frac{-8}{-11} can be simplified to \frac{8}{11} by removing the negative sign from both the numerator and the denominator.

$$x\leq \frac{8}{11}$$