Solve 9-2x=9/2+x

$$9-2x= \frac{ 9 }{ 2 } +x$$

Solve for x

$$x = \frac{3}{2} = 1\frac{1}{2} = 1.5$$

Steps for Solving Linear Equation

Subtract x from both sides.

$$9-2x-x=\frac{9}{2}$$

Combine -2x and -x to get -3x.

$$9-3x=\frac{9}{2}$$

Subtract 9 from both sides.

$$-3x=\frac{9}{2}-9$$

Convert 9 to fraction \frac{18}{2}.

$$-3x=\frac{9}{2}-\frac{18}{2}$$

Since \frac{9}{2} and \frac{18}{2} have the same denominator, subtract them by subtracting their numerators.

$$-3x=\frac{9-18}{2}$$

Subtract 18 from 9 to get -9.

$$-3x=-\frac{9}{2}$$

Divide both sides by -3.

$$x=\frac{-\frac{9}{2}}{-3}$$

Express \frac{-\frac{9}{2}}{-3} as a single fraction.

$$x=\frac{-9}{2\left(-3\right)}$$

Multiply 2 and -3 to get -6.

$$x=\frac{-9}{-6}$$

Reduce the fraction \frac{-9}{-6} to lowest terms by extracting and canceling out -3.

$$x=\frac{3}{2}$$