Solve 9(-4-3/2y)-2z=28

$$9(-4- \frac{ 3 }{ 2 } y)-2z=28$$

Solve for y

$$y=\frac{-4z-128}{27}$$

Steps for Solving Linear Equation

Use the distributive property to multiply 9 by -4-\frac{3}{2}y.

$$-36-\frac{27}{2}y-2z=28$$

Add 36 to both sides.

$$-\frac{27}{2}y-2z=28+36$$

Add 28 and 36 to get 64.

$$-\frac{27}{2}y-2z=64$$

Add 2z to both sides.

$$-\frac{27}{2}y=64+2z$$

The equation is in standard form.

$$-\frac{27}{2}y=2z+64$$

Divide both sides of the equation by -\frac{27}{2}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{-\frac{27}{2}y}{-\frac{27}{2}}=\frac{2z+64}{-\frac{27}{2}}$$

Dividing by -\frac{27}{2} undoes the multiplication by -\frac{27}{2}.

$$y=\frac{2z+64}{-\frac{27}{2}}$$

Divide 64+2z by -\frac{27}{2} by multiplying 64+2z by the reciprocal of -\frac{27}{2}.

$$y=\frac{-4z-128}{27}$$

Solve for z

$$z=-\frac{27y}{4}-32$$

Steps for Solving Linear Equation

Use the distributive property to multiply 9 by -4-\frac{3}{2}y.

$$-36-\frac{27}{2}y-2z=28$$

Add 36 to both sides.

$$-\frac{27}{2}y-2z=28+36$$

Add 28 and 36 to get 64.

$$-\frac{27}{2}y-2z=64$$

Add \frac{27}{2}y to both sides.

$$-2z=64+\frac{27}{2}y$$

The equation is in standard form.

$$-2z=\frac{27y}{2}+64$$

Divide both sides by -2.

$$\frac{-2z}{-2}=\frac{\frac{27y}{2}+64}{-2}$$

Dividing by -2 undoes the multiplication by -2.

$$z=\frac{\frac{27y}{2}+64}{-2}$$

Divide 64+\frac{27y}{2} by -2.

$$z=-\frac{27y}{4}-32$$