Solve 9,11*10^-31*(3*10^8)^2

$$9,11 \cdot 10 ^ { - 31 } \cdot ( 3 \cdot 10 ^ { 8 } ) ^ { 2 }$$

Evaluate

$$0,00000000000008199$$

Solution Steps

Calculate 10 to the power of -31 and get \frac{1}{10000000000000000000000000000000}.

$$9,11\times \frac{1}{10000000000000000000000000000000}\times \left(3\times 10^{8}\right)^{2}$$

Multiply 9,11 and \frac{1}{10000000000000000000000000000000} to get \frac{911}{1000000000000000000000000000000000}.

$$\frac{911}{1000000000000000000000000000000000}\times \left(3\times 10^{8}\right)^{2}$$

Calculate 10 to the power of 8 and get 100000000.

$$\frac{911}{1000000000000000000000000000000000}\times \left(3\times 100000000\right)^{2}$$

Multiply 3 and 100000000 to get 300000000.

$$\frac{911}{1000000000000000000000000000000000}\times 300000000^{2}$$

Calculate 300000000 to the power of 2 and get 90000000000000000.

$$\frac{911}{1000000000000000000000000000000000}\times 90000000000000000$$

Multiply \frac{911}{1000000000000000000000000000000000} and 90000000000000000 to get \frac{8199}{100000000000000000}.

$$\frac{8199}{100000000000000000}$$

Factor

$$\frac{911 \cdot 3 ^ {2}}{2 ^ {17} \cdot 5 ^ {17}} = 8.199 \times 10^{-14}$$