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\left(3y^{3}-rp^{6}\right)\left(3y^{3}+rp^{6}\right)
Rewrite 9y^{6}-r^{2}p^{12} as \left(3y^{3}\right)^{2}-\left(rp^{6}\right)^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).