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\left(3y^{2}-2x^{3}\right)\left(3y^{2}+2x^{3}\right)
Rewrite 9y^{4}-4x^{6} as \left(3y^{2}\right)^{2}-\left(2x^{3}\right)^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).
\left(-2x^{3}+3y^{2}\right)\left(2x^{3}+3y^{2}\right)
Reorder the terms.