Solve for x
x=\frac{2y}{3}+3
Solve for y
y=\frac{3\left(x-3\right)}{2}
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9x-27=6y
Add 6y to both sides. Anything plus zero gives itself.
9x=6y+27
Add 27 to both sides.
\frac{9x}{9}=\frac{6y+27}{9}
Divide both sides by 9.
x=\frac{6y+27}{9}
Dividing by 9 undoes the multiplication by 9.
x=\frac{2y}{3}+3
Divide 6y+27 by 9.
-6y-27=-9x
Subtract 9x from both sides. Anything subtracted from zero gives its negation.
-6y=-9x+27
Add 27 to both sides.
-6y=27-9x
The equation is in standard form.
\frac{-6y}{-6}=\frac{27-9x}{-6}
Divide both sides by -6.
y=\frac{27-9x}{-6}
Dividing by -6 undoes the multiplication by -6.
y=\frac{3x-9}{2}
Divide -9x+27 by -6.
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y = 3x + 4
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Simultaneous equation
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Differentiation
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
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Limits
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