Solve for x
x=\frac{4y}{9}+\frac{2}{3}
Solve for y
y=\frac{9x}{4}-\frac{3}{2}
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9x=6+4y
Add 4y to both sides.
9x=4y+6
The equation is in standard form.
\frac{9x}{9}=\frac{4y+6}{9}
Divide both sides by 9.
x=\frac{4y+6}{9}
Dividing by 9 undoes the multiplication by 9.
x=\frac{4y}{9}+\frac{2}{3}
Divide 6+4y by 9.
-4y=6-9x
Subtract 9x from both sides.
\frac{-4y}{-4}=\frac{6-9x}{-4}
Divide both sides by -4.
y=\frac{6-9x}{-4}
Dividing by -4 undoes the multiplication by -4.
y=\frac{9x}{4}-\frac{3}{2}
Divide 6-9x by -4.
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