Solve for x
x=\frac{y+9}{3}
Solve for y
y=3\left(x-3\right)
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9x=27+3y
Add 3y to both sides.
9x=3y+27
The equation is in standard form.
\frac{9x}{9}=\frac{3y+27}{9}
Divide both sides by 9.
x=\frac{3y+27}{9}
Dividing by 9 undoes the multiplication by 9.
x=\frac{y}{3}+3
Divide 27+3y by 9.
-3y=27-9x
Subtract 9x from both sides.
\frac{-3y}{-3}=\frac{27-9x}{-3}
Divide both sides by -3.
y=\frac{27-9x}{-3}
Dividing by -3 undoes the multiplication by -3.
y=3x-9
Divide 27-9x by -3.
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