Solve for x
x=\frac{y+6}{3}
Solve for y
y=3\left(x-2\right)
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9x=18+3y
Add 3y to both sides.
9x=3y+18
The equation is in standard form.
\frac{9x}{9}=\frac{3y+18}{9}
Divide both sides by 9.
x=\frac{3y+18}{9}
Dividing by 9 undoes the multiplication by 9.
x=\frac{y}{3}+2
Divide 18+3y by 9.
-3y=18-9x
Subtract 9x from both sides.
\frac{-3y}{-3}=\frac{18-9x}{-3}
Divide both sides by -3.
y=\frac{18-9x}{-3}
Dividing by -3 undoes the multiplication by -3.
y=3x-6
Divide 18-9x by -3.
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