Solve 9x-12y-4=0

$$9 x - 12 y - 4 = 0$$

Solve for x

$$x=\frac{4y}{3}+\frac{4}{9}$$

Steps for Solving Linear Equation

Add 12y to both sides. Anything plus zero gives itself.

$$9x-4=12y$$

Add 4 to both sides.

$$9x=12y+4$$

Divide both sides by 9.

$$\frac{9x}{9}=\frac{12y+4}{9}$$

Dividing by 9 undoes the multiplication by 9.

$$x=\frac{12y+4}{9}$$

Divide 12y+4 by 9.

$$x=\frac{4y}{3}+\frac{4}{9}$$

Solve for y

$$y=\frac{3x}{4}-\frac{1}{3}$$

Steps for Solving Linear Equation

Subtract 9x from both sides. Anything subtracted from zero gives its negation.

$$-12y-4=-9x$$

Add 4 to both sides.

$$-12y=-9x+4$$

The equation is in standard form.

$$-12y=4-9x$$

Divide both sides by -12.

$$\frac{-12y}{-12}=\frac{4-9x}{-12}$$

Dividing by -12 undoes the multiplication by -12.

$$y=\frac{4-9x}{-12}$$

Divide -9x+4 by -12.

$$y=\frac{3x}{4}-\frac{1}{3}$$