Solve 9x-(5x+1)-(2+8x-[7x-5]]+ax=0

$$9 x - ( 5 x + 1 ) - ( 2 + 8 x - [ 7 x - 5 ] ] + a x = 0$$

Solve for a

$$a=-3+\frac{8}{x}$$

$$x\neq 0$$

Steps for Solving Linear Equation

To find the opposite of 5x+1, find the opposite of each term.

$$9x-5x-1-\left(2+8x-\left(7x-5\right)\right)+ax=0$$

Combine 9x and -5x to get 4x.

$$4x-1-\left(2+8x-\left(7x-5\right)\right)+ax=0$$

To find the opposite of 7x-5, find the opposite of each term.

$$4x-1-\left(2+8x-7x+5\right)+ax=0$$

Combine 8x and -7x to get x.

$$4x-1-\left(2+x+5\right)+ax=0$$

Add 2 and 5 to get 7.

$$4x-1-\left(7+x\right)+ax=0$$

To find the opposite of 7+x, find the opposite of each term.

$$4x-1-7-x+ax=0$$

Subtract 7 from -1 to get -8.

$$4x-8-x+ax=0$$

Combine 4x and -x to get 3x.

$$3x-8+ax=0$$

Subtract 3x from both sides. Anything subtracted from zero gives its negation.

$$-8+ax=-3x$$

Add 8 to both sides.

$$ax=-3x+8$$

The equation is in standard form.

$$xa=8-3x$$

Divide both sides by x.

$$\frac{xa}{x}=\frac{8-3x}{x}$$

Dividing by x undoes the multiplication by x.

$$a=\frac{8-3x}{x}$$

Divide -3x+8 by x.

$$a=-3+\frac{8}{x}$$

Solve for x

$$x=\frac{8}{a+3}$$

$$a\neq -3$$

Steps for Solving Linear Equation

To find the opposite of 5x+1, find the opposite of each term.

$$9x-5x-1-\left(2+8x-\left(7x-5\right)\right)+ax=0$$

Combine 9x and -5x to get 4x.

$$4x-1-\left(2+8x-\left(7x-5\right)\right)+ax=0$$

To find the opposite of 7x-5, find the opposite of each term.

$$4x-1-\left(2+8x-7x+5\right)+ax=0$$

Combine 8x and -7x to get x.

$$4x-1-\left(2+x+5\right)+ax=0$$

Add 2 and 5 to get 7.

$$4x-1-\left(7+x\right)+ax=0$$

To find the opposite of 7+x, find the opposite of each term.

$$4x-1-7-x+ax=0$$

Subtract 7 from -1 to get -8.

$$4x-8-x+ax=0$$

Combine 4x and -x to get 3x.

$$3x-8+ax=0$$

Add 8 to both sides. Anything plus zero gives itself.

$$3x+ax=8$$

Combine all terms containing x.

$$\left(3+a\right)x=8$$

The equation is in standard form.

$$\left(a+3\right)x=8$$

Divide both sides by 3+a.

$$\frac{\left(a+3\right)x}{a+3}=\frac{8}{a+3}$$

Dividing by 3+a undoes the multiplication by 3+a.

$$x=\frac{8}{a+3}$$