Solve 9x-2/y=3

$$9 x - \frac { 2 } { y } = 3$$

Solve for x

$$x=\frac{1}{3}+\frac{2}{9y}$$

$$y\neq 0$$

Steps for Solving Linear Equation

Multiply both sides of the equation by y.

$$9xy-2=3y$$

Add 2 to both sides.

$$9xy=3y+2$$

The equation is in standard form.

$$9yx=3y+2$$

Divide both sides by 9y.

$$\frac{9yx}{9y}=\frac{3y+2}{9y}$$

Dividing by 9y undoes the multiplication by 9y.

$$x=\frac{3y+2}{9y}$$

Divide 3y+2 by 9y.

$$x=\frac{1}{3}+\frac{2}{9y}$$

Solve for y

$$y=-\frac{2}{3\left(1-3x\right)}$$

$$x\neq \frac{1}{3}$$

Steps for Solving Linear Equation

Variable y cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by y.

$$9xy-2=3y$$

Subtract 3y from both sides.

$$9xy-2-3y=0$$

Add 2 to both sides. Anything plus zero gives itself.

$$9xy-3y=2$$

Combine all terms containing y.

$$\left(9x-3\right)y=2$$

Divide both sides by 9x-3.

$$\frac{\left(9x-3\right)y}{9x-3}=\frac{2}{9x-3}$$

Dividing by 9x-3 undoes the multiplication by 9x-3.

$$y=\frac{2}{9x-3}$$

Divide 2 by 9x-3.

$$y=\frac{2}{3\left(3x-1\right)}$$

Variable y cannot be equal to 0.

$$y=\frac{2}{3\left(3x-1\right)}\text{, }y\neq 0$$