Solve 9x-[3(x+2)-(x-1)]=0

$$9 x - [ 3 ( x + 2 ) - ( x - 1 ) ] = 0$$

Solve for x

$$x=1$$

Steps for Solving Linear Equation

Use the distributive property to multiply 3 by x+2.

$$9x-\left(3x+6-\left(x-1\right)\right)=0$$

To find the opposite of x-1, find the opposite of each term.

$$9x-\left(3x+6-x-\left(-1\right)\right)=0$$

The opposite of -1 is 1.

$$9x-\left(3x+6-x+1\right)=0$$

Combine 3x and -x to get 2x.

$$9x-\left(2x+6+1\right)=0$$

Add 6 and 1 to get 7.

$$9x-\left(2x+7\right)=0$$

To find the opposite of 2x+7, find the opposite of each term.

$$9x-2x-7=0$$

Combine 9x and -2x to get 7x.

$$7x-7=0$$

Add 7 to both sides. Anything plus zero gives itself.

$$7x=7$$

Divide both sides by 7.

$$x=\frac{7}{7}$$

Divide 7 by 7 to get 1.

$$x=1$$