Solve 9x*-2x-5

$$9 x \cdot - 2 x - 5$$

Evaluate

$$-18x^{2}-5$$

Solution Steps

Multiply x and x to get x^{2}.

$$9x^{2}\left(-2\right)-5$$

Multiply 9 and -2 to get -18.

$$-18x^{2}-5$$

Differentiate w.r.t. x

$$-36x$$

Steps Using Derivative Rule for Sum

Multiply x and x to get x^{2}.

$$\frac{\mathrm{d}}{\mathrm{d}x}(9x^{2}\left(-2\right)-5)$$

Multiply 9 and -2 to get -18.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-18x^{2}-5)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$2\left(-18\right)x^{2-1}$$

Multiply 2 times -18.

$$-36x^{2-1}$$

Subtract 1 from 2.

$$-36x^{1}$$

For any term t, t^{1}=t.

$$-36x$$