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\left(3x^{2}y-11\right)\left(3x^{2}y+11\right)
Rewrite 9x^{4}y^{2}-121 as \left(3x^{2}y\right)^{2}-11^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).
\left(3yx^{2}-11\right)\left(3yx^{2}+11\right)
Reorder the terms.