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Solve for x (complex solution)
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9t^{2}+6t-8=0
Substitute t for x^{2}.
t=\frac{-6±\sqrt{6^{2}-4\times 9\left(-8\right)}}{2\times 9}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Substitute 9 for a, 6 for b, and -8 for c in the quadratic formula.
t=\frac{-6±18}{18}
Do the calculations.
t=\frac{2}{3} t=-\frac{4}{3}
Solve the equation t=\frac{-6±18}{18} when ± is plus and when ± is minus.
x=-\frac{\sqrt{6}}{3} x=\frac{\sqrt{6}}{3} x=-\frac{2\sqrt{3}i}{3} x=\frac{2\sqrt{3}i}{3}
Since x=t^{2}, the solutions are obtained by evaluating x=±\sqrt{t} for each t.
9t^{2}+6t-8=0
Substitute t for x^{2}.
t=\frac{-6±\sqrt{6^{2}-4\times 9\left(-8\right)}}{2\times 9}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Substitute 9 for a, 6 for b, and -8 for c in the quadratic formula.
t=\frac{-6±18}{18}
Do the calculations.
t=\frac{2}{3} t=-\frac{4}{3}
Solve the equation t=\frac{-6±18}{18} when ± is plus and when ± is minus.
x=\frac{\sqrt{6}}{3} x=-\frac{\sqrt{6}}{3}
Since x=t^{2}, the solutions are obtained by evaluating x=±\sqrt{t} for positive t.