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\left(3xy^{2}-4z^{3}\right)\left(3xy^{2}+4z^{3}\right)
Rewrite 9x^{2}y^{4}-16z^{6} as \left(3xy^{2}\right)^{2}-\left(4z^{3}\right)^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).